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1
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G1 ~ X1 n Y, ~ X,= ~(t,) a.J Y, = ~('J,). !3d 1 ~ ?1 ~ ~
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s
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.
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<-xa..J4 · f
~ so tk ~ ~ &/G-' v., lk ~ J·~cl #f B-,/cr' ~ 61/G-'.
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~
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l G; ':::; G- I J_., .
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~ G.'-= { J} :~ ~ .ta.=
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wLu.c.
wLi1... r ~~~
G-1 -::..{t_,
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G-
c-.L
2 .
1J-= 1 . ~ G- =- G-, G-:1.
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= {t,(,. ?.,.} · 7L,... G- -=- G,*
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G-:
~
, c..~
c-;~~-
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Let-
c..:
10
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/t..u., ~ G-;). , w1.:!. 0 61 c.--r~ I() •
M 4J'tC. J~~ .) ~ ~ C~h..tJ
J,..+ 33 (~)
3r(f) + ..... -=- f.~(/+3)"- (1-3) ...}-: 1-yo_,
"f crr-l.,r '+ ; ~ 0~,__, c.n.f.:.... <.~~-2-...,. zr-'( ,....
_,.
J
{2.W:..(:-1)...
-+ (
~el:c.. . s~
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S. ~.,.. ~ 0 ~..,._, ~ ....,t ~
'1- o-rcA,.. It-.
~cl.:c. .ru.-4~
2..,.
+
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c.O ~·c.. •
Ld f ~.. ~ . lf G i. 1 .tt..'f./'~.J; f , ~ Ji. I~ CA..trd
fo.d-flf:' C.~ . ~t k oJ- lj~ P =- 1f, ~ Cl-J J" G- -= P .,.._ If w -'"'1t'u.C-C
fr ~ (.fit f'- ~ r*"r . Lei- c;. = G-, ~~ ~ c.. : = (f..::·'"1 a..J [G,c.~=-j
(!!iJ
lkiL
(f* J ~.
t! =
ftc:, ?,a ~ G-f ) ~
lAk ~
G;~:. { t, r.l.
1/ ..
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i=-1_,2..
So c;. ~ 1-
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JM r,t~ ~ 1 ~f";.
74,.
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ih ~~r,
G ,; fL_ ~,...t- ~ G-,*" ~: • ~ &j'" io ~ 1- /;jtL 1'~ -for.
' ~ G- wov..l) Lt.. ~ ~,~ f , );r l't-·:1.4-.
If G- = G, G~ ... G-r ~ f '1J" f*f_,._, 4
G~ , . -~ , G.r 'f lfl~ f --->
G~ -= {$, , ,, } -/ far f"', ~
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U:Ju. f . If ' (, /~ J.u:c.cl ~cf 1- · {!J,'J .M:/J. ?~~C.r 'If ~ ]'r-~
0 ...
~ /JAC
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z
So
c;:- .;,
'1,';_
L~ l'f..J,-J
If G. :.._ '" ;-~ .r...,J. lta.t- ~'=-1-G ;, 1 ~r /' ~
/A,.. ~ ~~Jr-. 1-- G ~ +~r- 6-/i;.' L~ u <h
iil\tU.r J~~.
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u
rl..,...
r,
ar o.4'~:~L. -
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fk "~
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1' <;.
lr I G-: J-t;./ , lk '"~ 1' ~~ ~~ 1- G --~
~~ G-/G! L·~·~ • He...u.. ~ ~u..tr.
u..
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l.1k
~
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If
C
=H
Theorem 14.3
Suppooe
implies that
C
C =G.
that
, it is an easy consequence of Theorem 14.3 that
::>
H and
Let
G1 =
p
is odd •
~(G).H •
c ::>H
)
S
O8 Qs'
8
G
=
s
s' z. , where
1
If
= ~ (C).c(.Q 1 (C))
subgroup of
C( 121 (c))
tY
~
, P
~
Since 4t/C
,
Q·
~
•
Then
•
is cyclic, Theorem 14.3 implies
By Lemma 14.41,
C
=2
l Hl /
2 •
z1 = .C22 (H)
08 Q
8
and . H •
0
p
am
from Theorem 14.1 , so suppose
1 (C
is one of
=2
G
= G1C(G1 )
and so
G
= G1
•
G = Pr H , and we are done.
By Lemma 14.4, we have
Finally, suppose
G
p
=G
If
IH
l
Since
•
== 2 ' the :i::elmll
C1
Thus,
Furt~ermore,
It follows that
theorem follows
is of order 2 , it follows that
C is the central product of
, the proof is complete.
by Lemma 14.41.
•
•
C( ~ (C))
Otherwise, we get
H is a maximal aorma.l abelian
is one of
The various ismorphisms follow easily from Theorem 14.4.
A
P k, Q k, 0 k •
2
2
2 .
.
.
r
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LG- J Let H
~ ; .., z
~
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o..
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J\Ot• ..1,
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/1.».. ~ a.. ~~ .t~~ I< -r G. s-.J. /J,.J,; H < K. s G-. 1 -~J
IK ~ HI-=-;. n.... K Co )\,f; CAJ~ • II I< it, MeL.~ it .:- 'I iaJ'L
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'I
~ /> = 2. ;~kJ ~ (;, 1 ~ 2., ~J lcr·.J (!v) • 7k. ~ ~~ ~
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7
13o
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a-J
~
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/r..J: } 6-'
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, [M , G-1] = 1. . 7L:.
l.h..
7k... /i<JG-
e,.J-~-J;, 11;,_ t~U.q_,t~
<:! d.: c... •
&.
f~
~~ ~
~ c.~t:.~ J~ M=.n.,K 'I~ }"L·
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to ,
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c.t ih "'J~ I 1-3 ~~~ • . f.k..CL (;./ ;. 4./ckc.. LJ l'f-·SI' a-J ZG' ~ A..
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c.. t.rocw
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c.Jv.-..~~
.,
1
lit-·!>.
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a-.vi if C -:. CG- (H), /A,. ;, C ;,. " ~~ Al,<l.·a.. .s~r-tltAf 1 Gc,.,J-~ fl ·~ k-c.c.. J- C ~ 'teL:c. , ~J .r. J-C. -=H .
If
1k C ~ 1 cl.a.u
C ,_ H,
t'J 1·1 Ul _,(iiJ.
lj
~ -~'.a.
:?;:
•
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~.
[ f,' .) 'fc: J
,
....~
2
At,., C/ ~ G-/ ~ H ;::.A-C.
~sJ ... [f,r,J.,..r -for «11. {,' ~
ftr,
l..d . 14 Ak£;_ frt'? C/H k 1 'i~
w '-t
H! I
= [ r, > fc:r~~1 '::.
,
Hl ~
.) .-- k
~ .: =
1
I
M\H.
c.;H .
l Mk 1
a.
2. ,3.) --
/> r,- •
a...J
,.,., -•
b
-1UACL
t;
l
r.t, · --) ,
7l..t,~
1,
,~-2..
E
w<
c,
~
~
H -~c.
.
t.,c J =- f'fc: , t: J = :l frr
All.. i .~j-.
If L/H = v;,:..., (C/H), d {:ft ~vwlt;..t L cLr ~ , L/-== L , '- /H:.
~ L 7chc.. , ~~":/ k ft.. c.Lh.u.. "' H.. '*-'u. r 1 = .l ~J C./ H .:..
~~' cw..J .to C 1 &- 1- ~ !·
J.k..~
fj
-=
r:a. •
/f
1j
~
I ,
we.
[
fi
>